Binary operations in Lisp

hello everyone. i am new to Lisp. i dont know how to perform binary operations in LISP?
can anyone share sample of code for binary addition or multiplication plz

A binary operation is treated as any other n-ary operation. There is nothing special about it. Use prefix notation:

(+ 1 2) ; = 3
(* 2 3) ; = 6

Integers don't have base when they are stored. Your reader can read numbers in several different bases.

(+ 10 #xa #b1010) ; ==> 30 

Now when makeing a string out of the number you get to choose the base:

(let ((thirty (+ 10 #xa #b1010)))
  (format nil "~n ~x ~o ~b" thirty thirty thirty thirty))
; ==> "30 1E 36 11110"

There you have it. 30 displayed in 4 different bases. In CL you have the special variable *print-base* which sets the default base in which numbers are printed and *read-base* which sets the default base in which numbers are read when parsed:

(let ((*print-base* 16)
        (*read-base* 2))
  (princ (read-from-string "1011"))) ; ==> B

Thats about all there is to know about displaying and parsing numbers. Now all your base are belong to you

I think the question was about binary operations (operations that take exactly two arguments), not how to compute numbers represented in binary format. And the question smells very much like homework...