Re: Replacing a function in an expression
Posted: Fri Nov 16, 2012 10:15 pm
When formulating your problem, you should also think about lexical closures. Assume your piece of LISP code contains the following fragment:
Are you sure you want to replace function occurences of LIST by "mylist" even in this fragment , inside flet?
Code: Select all
(flet ((list (&rest argument) ......... definition ..........))
(LIST a b)
(LIST c d e)
.... et cetera ......
)