You have problems, and we're glad to hear them. Explain the problem, what you have tried, and where you got stuck.
Feel free to share a little info on yourself and the course.
Forum rules
Please respect your teacher's guidelines. Homework is a learning tool. If we just post answers, we aren't actually helping. When you post questions, be sure to show what you have tried or what you don't understand.

dgfrey102790
 Posts: 2
 Joined: Sat Sep 01, 2018 7:07 pm
Post
by dgfrey102790 » Sat Sep 01, 2018 7:12 pm
I'm very new to Lisp.
I'm trying to make a product function that takes in an arbitrary parameter x. The function should return the product of all numeric values contained within x. For example,
> (product ’x) 1
> (product ’(x 5)) 5
> (product ’((2 2) 3) ) 12
> (product ’((a 3) (2 1)) ) 6
I've been given the hint to use consp and numberp. I was able to figure out if the parameter is just 'x > 1, or if it's like '(2 5) > 10. What I can't figure out is how to deal with a letter and a number, or dealing with sublists.
Here's what I've done so far:
Code: Select all
(defun product (x)
"This function takes in an arbitrary parameter x, and returns the product of all numeric values contained within x."
(cond
((consp x) (* (car x)(cadr x)))
((numberp x) x)
(t 1)
)
)

nuntius
 Posts: 538
 Joined: Sat Aug 09, 2008 10:44 am
 Location: Newton, MA
Post
by nuntius » Sun Sep 02, 2018 12:47 pm
There are a few ways to do this.
I would guess that you are supposed to use recursion for complex forms.
In other words, have the product function call product on smaller pieces of the input.

dgfrey102790
 Posts: 2
 Joined: Sat Sep 01, 2018 7:07 pm
Post
by dgfrey102790 » Tue Sep 04, 2018 11:45 am
Thanks. I got it with recursion.
Here's what I was able to figure out:
Code: Select all
(defun product (x)
"This function takes in an arbitrary parameter x, and returns the product of all numeric values contained within x."
(cond
((consp x) (* (product (car x)) (product (cdr x))))
((numberp x) (* x 1))
(t 1)
)
)
;tests
(print (product '((2 2) 3))) > 12
(print (product '(3 5))) > 15
(print (product 'x)) > 1
(print (product '('x 5))) > 5
(print (product '((a 3) (2 1)))) > 6