Now I have another doubt.

I have a bit of difficulty making those tables for iterative processes and needed help to make one for this problem:

Consider a procedure called "adder" that when we give a natural n ir returns the sum of all odd natural smaller than n if n is even and the sum of all natural pairs smaller than n where n is odd.

Sry for my english

Statistics: Posted by PORCOREAL — Thu Oct 23, 2014 8:58 am

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- Code:
`(define (enequa n)`

(if (< n 1)

1

(* (if (odd? n) n 1)

(enequa (- n 1)))))

Statistics: Posted by Goheeca — Fri Oct 17, 2014 1:55 pm

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(enequa 5) = 1x3x5x7x9 = 945

(enequa 1) = 1

(enequa -2) = 1

should start

(define (enequa n)

i need help because i have o know answer to this problem after my mondy test

Statistics: Posted by PORCOREAL — Thu Oct 16, 2014 7:46 am

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Statistics: Posted by saulgoode — Fri Apr 25, 2014 1:25 pm

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add is not included so you get an error.

You can tell by just type inn identifiers in the interactions window before you define them and like sqrt you'll see #<procedure:sqrt> with sqrt replaced by something else.

The reason for this is unknown but I imagine it has to do with sqrt being a standard procedure in RNRS Scheme and Racket. If the package is based on one R5RS (the closest language to R3RS which were used in SICP) you will have all of the R5RS procedure and syntax that are not in direct violation of R3RS.

Statistics: Posted by sylwester — Mon Apr 21, 2014 1:44 pm

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The following codes are from the book and I use the procedure "sqrt" at beginning:

- Code:
`(sqrt (+ 100 37))`

(define (sqrt-iter guess x)

(if (good-enougth? guess x)

guess

(sqrt-iter (improve guess x)

x)))

(define (improve guess x)

(average guess (/ x guess)))

(define (average x y)

(/ (+ x y) 2))

(define (good-enougth? guess x)

(< (abs (- (square guess) x)) 0.001))

(define (square x)

(* x x))

(define (sqrt x)

(sqrt-iter 1.0 x))

It worked perfactly well. But as for my understanding, you have to define a procedure before use it, right? So I don't understand how this can work?

And I do an experiment:

- Code:
`(add 2 2)`

(define (add x y)

(test x y))

(define (test x y)

(+ x y))

But this time the interpreter gave me "add: undefined; cannot reference undefined identifier", so I am totally confused about these results, can somebody explain what's going to me?

Thank you

Statistics: Posted by blackdiz — Wed Apr 16, 2014 5:50 pm

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Statistics: Posted by nuntius — Sun Mar 02, 2014 8:44 pm

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Is this a homework problem?

Statistics: Posted by nuntius — Thu Oct 03, 2013 9:18 am

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